Question

Участок цепи состоит из 2-ух лампочек сопротивлением 0.2кОм ,соединенных параллельно . Последовательно к ним подключены 2 резистора сопротивлением 100 Ом и 300 Ом . Чему равно общее сопротивление этого участка схемы? Начертить схему.

Answer 1

Верхняя часть: 100+200=300 ом, нижняя 300+300=600 ом. Общее: 1/300+1/600=1/200=> R=200 Om

Answer 2

Calculation of Total Resistance

To calculate the total resistance of the circuit, we need to consider the resistances of the two parallel lamps and the two resistors connected in series.

The resistance of the two lamps connected in parallel is given as 0.2 kΩ. Since they are connected in parallel, the total resistance of the lamps can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

where R1 and R2 are the resistances of the individual lamps.

Plugging in the given resistance value of 0.2 kΩ for both lamps, we get:

1/R_total = 1/0.2 kΩ + 1/0.2 kΩ

Simplifying this equation, we find:

1/R_total = 2/0.2 kΩ

To find the total resistance, we take the reciprocal of both sides:

R_total = 0.2 kΩ / 2

Simplifying further, we get:

R_total = 0.1 kΩ

Now, let's calculate the total resistance of the two resistors connected in series. The resistances of the two resistors are given as 100 Ω and 300 Ω.

To find the total resistance of resistors connected in series, we simply add the individual resistances:

R_total = R1 + R2

Plugging in the given resistance values, we get:

R_total = 100 Ω + 300 Ω

Simplifying this equation, we find:

R_total = 400 Ω

Total Resistance of the Circuit

To find the total resistance of the circuit, we need to add the total resistance of the lamps (0.1 kΩ) and the total resistance of the resistors (400 Ω) connected in series:

Total Resistance = R_lamps + R_resistors

Plugging in the calculated values, we get:

Total Resistance = 0.1 kΩ + 400 Ω

Converting the units to a common one, we have:

Total Resistance = 0.1 kΩ + 0.4 kΩ

Simplifying this equation, we find:

Total Resistance = 0.5 kΩ

Therefore, the total resistance of this circuit is 0.5 kΩ.

Circuit Diagram

Here is a simple circuit diagram representing the given circuit configuration:

``` Lamp 1 Lamp 2 0.2kΩ 0.2kΩ | | | | | | | | | | ----- ----- | | | | | 100 | | 300 | | Ω | | Ω | | | | | ----- ----- | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |