Question

Із водню об'ємом 134,4 л (н. у.) й азоту в надлишку синтезували амоніак кількістю речовини 1,2 моль.Визначте відносний вихід продукту.

Answer 1

Ответ: 30%

Объяснение:

Answer 2

Calculation of Relative Yield of Ammonia

To calculate the relative yield of the product, we need to compare the actual amount of ammonia produced with the theoretical amount that could have been produced based on the reactants used.

Given: - Volume of hydrogen gas (H2) = 134.4 L (at normal conditions) - Volume of nitrogen gas (N2) = excess (not specified) - Amount of ammonia (NH3) produced = 1.2 mol

To determine the relative yield, we need to find the stoichiometric ratio between the reactants and the product. The balanced chemical equation for the synthesis of ammonia from hydrogen and nitrogen is:

N2 + 3H2 → 2NH3

From the balanced equation, we can see that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

Now, let's calculate the theoretical amount of ammonia that could have been produced based on the given volume of hydrogen gas:

1. Convert the volume of hydrogen gas to moles using the ideal gas law: - PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. - Since the pressure and temperature are not specified, we assume standard conditions (1 atm and 273 K). - Using the molar volume of an ideal gas at standard conditions (22.4 L/mol), we can calculate the number of moles of hydrogen gas: - Number of moles of hydrogen (H2) = Volume of hydrogen (H2) / Molar volume of hydrogen (H2) at standard conditions - Number of moles of hydrogen (H2) = 134.4 L / 22.4 L/mol = 6 mol

2. Determine the stoichiometric ratio between hydrogen and ammonia: - From the balanced equation, we know that 3 moles of hydrogen react to produce 2 moles of ammonia. - Therefore, the theoretical amount of ammonia that could have been produced from 6 moles of hydrogen is: - Theoretical moles of ammonia = (2 moles of ammonia / 3 moles of hydrogen) * 6 moles of hydrogen - Theoretical moles of ammonia = 4 mol

3. Calculate the relative yield of ammonia: - Relative yield = (Actual moles of ammonia / Theoretical moles of ammonia) * 100% - Relative yield = (1.2 mol / 4 mol) * 100% - Relative yield = 30%

Therefore, the relative yield of ammonia in this reaction is 30%.

Please note that the volume of nitrogen gas is not specified, so we cannot determine the exact stoichiometric ratio between nitrogen and ammonia. However, based on the given information, we can calculate the relative yield based on the hydrogen reactant.