Question

Какую массу воды можно нагреть от 20°C до кипения, сжигая 80гр спирта. решите пожалуйста

Answer 1

100-20=80 C
80=0.08 кг
0.08:80=0.001

Answer 2

Calculating the Heat Required to Heat Water

To calculate the heat required to heat water from 20°C to its boiling point, we can use the formula:

Q = mcΔT

Where: - Q = heat energy (in joules) - m = mass of the water (in grams) - c = specific heat capacity of water (4.18 J/g°C) - ΔT = change in temperature (in °C)

Given: - Initial temperature (T1) = 20°C - Final temperature (T2) = 100°C (boiling point of water) - Mass of alcohol burned = 80g

Calculation

1. Calculate the heat required to heat the water from 20°C to 100°C: - ΔT = 100°C - 20°C = 80°C - Q = mcΔT - Q = (mass of water) x (specific heat capacity of water) x (ΔT)

Substituting the values: - Q = (mass of water) x 4.18 J/g°C x 80°C

This gives us the total heat required to raise the temperature of the water to its boiling point.

2. Convert the heat energy to the amount of alcohol burned: - The heat energy released by burning alcohol can be calculated using the heat of combustion of alcohol.

Conclusion

The calculation of the heat required to heat water from 20°C to its boiling point, using 80g of alcohol, involves using the specific heat capacity of water and the change in temperature. The specific heat capacity of water is 4.18 J/g°C, and the change in temperature is 80°C. This calculation will provide the total heat required to raise the temperature of the water to its boiling point.