Question

1. Определить количество теплоты, переданное нагревателем тепловой машине за цикл (кДж), если её КПД составляет 70%, а в холодильник за цикл было выделено 311 кдж теплоты. Решать без округления (калькулятор или конечная формула)

Answer 1

Ответ:

1037 кДж

Объяснение:

n=0.7 (70%)    Qx=311 кДж    Qн=?

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n=(Qн-Qx)/Qн

Qн=Qx/(1-n)=311/(1-0.7)=1037 кДж

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Answer 2

Calculation of Heat Transferred by the Heater

To determine the amount of heat transferred by the heater in a cycle, we need to use the efficiency (η) of the heat engine and the amount of heat released by the refrigerator in a cycle.

Given: - Efficiency of the heat engine (η) = 70% - Heat released by the refrigerator in a cycle = 311 kJ

The efficiency of a heat engine is defined as the ratio of the useful work output to the heat input. In this case, the heat input is the heat transferred by the heater.

The formula to calculate the heat transferred by the heater is:

Heat transferred by the heater = Heat released by the refrigerator / Efficiency of the heat engine

Substituting the given values:

Heat transferred by the heater = 311 kJ / 0.70

Calculating the result:

Heat transferred by the heater = 444.29 kJ

Therefore, the amount of heat transferred by the heater to the heat engine in a cycle is approximately 444.29 kJ.