Question

. Какое количество энергии необходимо для плавления куска свинца массой 200 г, взятого при температуре плавления?

Answer 1

Дано:

tп = 327°С

m = 200 г = 0,2 кг

лямбда (л) = 0,25×10^5 Дж/кг

Q = ?

Анализ:

Q = л×m

Решение:

Q = 0,25×10^5×0,2 = 5 кДж

Ответ: 5 кДж

Answer 2

Energy Required to Melt Lead

To calculate the energy required to melt a piece of lead, we can use the formula:

Q = m * L

Where: - Q = energy required - m = mass of the substance - L = latent heat of fusion

Given: - Mass of lead, m = 200 g - Latent heat of fusion for lead, L = 24 J/g

Using the formula, we can calculate the energy required to melt the lead:

Q = 200 g * 24 J/g = 4800 J

Therefore, the energy required to melt a 200 g piece of lead at its melting temperature is 4800 Joules.