Question

Число полных электромагнитных колебаний в. идеальном колебательном контуре N=1,5*10в7 за промежуток времени t=10 с.на прием какой длины электромагнитной волны настроен данный контур ? скорость распростронения электромагнитных волн с=3,0*10в8м/с

Answer 1

За 1 секунду произойдёт в 10 раз меньше колебаний, то есть N1=N/10=1,5*10⁷/10=1,5*10⁶. То есть частота колебаний равна f=1,5*10⁶ Гц. Длина волны определяется как λ=c/f=3*10⁸/(1,5*10⁶)=200 метров.

Ответ: 200 метров.

Answer 2

Calculation of the Wavelength

To calculate the wavelength of the electromagnetic wave to which the given circuit is tuned, we can use the formula:

wavelength (λ) = speed of propagation (c) / frequency (f)

Given that the number of complete electromagnetic oscillations in the ideal oscillating circuit is N = 1.5 * 10^7 and the time interval is t = 10 s, we can calculate the frequency using the formula:

frequency (f) = N / t

Using the given speed of propagation of electromagnetic waves c = 3.0 * 10^8 m/s, we can substitute the values into the wavelength formula to find the wavelength.

Let's calculate it step by step:

1. Calculate the frequency: - N = 1.5 * 10^7 - t = 10 s - f = N / t

2. Calculate the wavelength: - c = 3.0 * 10^8 m/s - λ = c / f

Now let's perform the calculations:

1. Calculate the frequency: - N = 1.5 * 10^7 - t = 10 s - f = N / t = 1.5 * 10^7 / 10 = 1.5 * 10^6 Hz

2. Calculate the wavelength: - c = 3.0 * 10^8 m/s - λ = c / f = 3.0 * 10^8 / (1.5 * 10^6) = 200 m

Therefore, the given circuit is tuned to an electromagnetic wave with a wavelength of 200 meters.

[[1]](http://library.mephi.ru/pdftunnel.php?Z21FAMILY=%D0%A1%D1%82%D1%83%D0%BA%D0%B0%D0%BB%D0%BE%D0%B2%D0%B0&Z21ID=01635&PATH=book-mephi%2FKalashnikov_Rukovodstvo_po_resheniyu_zadach_po_obshchey_fizike_Kolebatelnoe_dvizhenie_2015.pdf)