Question

Вертолёт массой 7 тонны равномерно приземляется со скоростью 36 км ч Чему равна его полная механическая энергия на высоте 500 м ПОМОГИТЕ ​

Answer 1

Ответ:

49

Объяснение:

Полная механическая энергия складывается из потенциальной и кинетической энергии, то есть:

E=En + Ek = mgh + mv²/2

En = mgh

Ek = mv² / 2

СИ:

7 т = 7000 кг

2 км = 2000 м

36 км/ч = 10 м / с

Находим полную механическую энергию:

E = 7000*10* 2000 + 7000* 100 / 2 = 14*10^7 +3.5*10^5 = 49 * 10^12 Д* = 49

ТДж

Answer 2

Calculation of the Helicopter's Total Mechanical Energy

To calculate the total mechanical energy of the helicopter at a height of 500 meters, we need to consider both its kinetic energy and potential energy.

1. Kinetic Energy (KE): The kinetic energy of an object is given by the formula KE = (1/2)mv^2, where m is the mass of the object and v is its velocity.

Given that the mass of the helicopter is 7 tons (which is equivalent to 7000 kilograms) and its velocity is 36 km/h (which is equivalent to 10 m/s), we can calculate the kinetic energy as follows:

KE = (1/2) * 7000 kg * (10 m/s)^2 = 350,000 J

2. Potential Energy (PE): The potential energy of an object at a certain height is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.

Given that the height is 500 meters, we can calculate the potential energy as follows:

PE = 7000 kg * 9.8 m/s^2 * 500 m = 34,300,000 J

3. Total Mechanical Energy (E): The total mechanical energy is the sum of the kinetic energy and potential energy:

E = KE + PE = 350,000 J + 34,300,000 J = 34,650,000 J

Therefore, the total mechanical energy of the helicopter at a height of 500 meters is 34,650,000 Joules.

Please note that the above calculation assumes that there are no other external forces acting on the helicopter, such as air resistance or friction.