Question

1. Електроскопу надали заряд -6,4 нКл. Скільки надлишкових електронів отримав електроскоп? 2. Визначте модуль напруженості електричного поля, у якому перебуває у рівновазі порошинка, маса якої 1г і заряд 10 нКл. 3. Заряди двох однакових металевих куль дорівнюють -5,5 н Кл та +1,5 нКл. Визначте заряд кожної кульки після дотику.

Answer 1

Відповідь: Див. додаток

Пояснення:

Answer 2

1. Електроскопу надали заряд -6,4 нКл. Скільки надлишкових електронів отримав електроскоп?

To determine the number of excess electrons acquired by the electroscope, we need to use the formula:

Q = ne

Where: - Q is the charge acquired by the electroscope - n is the number of excess electrons - e is the elementary charge (1.6 x 10^-19 C)

Given that the electroscope has a charge of -6.4 nC (negative charge), we can rearrange the formula to solve for n:

n = Q / e

Substituting the values:

n = -6.4 nC / (1.6 x 10^-19 C)

Calculating this, we find:

n ≈ -4 x 10^13 excess electrons

Therefore, the electroscope has acquired approximately -4 x 10^13 excess electrons [[1]].

2. Визначте модуль напруженості електричного поля, у якому перебуває у рівновазі порошинка, маса якої 1 г і заряд 10 нКл.

To determine the magnitude of the electric field in which the particle is in equilibrium, we can use the formula:

E = F / q

Where: - E is the electric field - F is the electrostatic force - q is the charge of the particle

In this case, the particle has a mass of 1 g and a charge of 10 nC. The electrostatic force acting on the particle can be calculated using Newton's second law:

F = mg

Where: - m is the mass of the particle - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the values:

F = (1 g) x (9.8 m/s^2)

Next, we can calculate the electric field:

E = F / q

Substituting the values:

E = [(1 g) x (9.8 m/s^2)] / (10 nC)

Converting the mass to kilograms and the charge to coulombs:

E = [(0.001 kg) x (9.8 m/s^2)] / (10 x 10^-9 C)

Calculating this, we find:

E ≈ 9.8 x 10^6 N/C

Therefore, the magnitude of the electric field in which the particle is in equilibrium is approximately 9.8 x 10^6 N/C [[2]].

3. Заряди двох однакових металевих куль дорівнюють -5,5 нКл та 1,5 нКл. Визначте заряд кожної кульки після дотику.

When two conductive objects with different charges come into contact, charge transfer occurs until both objects reach the same potential. This means that the final charges of the two spheres will be equal.

In this case, we have two metal spheres with charges of -5.5 nC and 1.5 nC. After they come into contact, the charges will redistribute until they are equal.

The final charge of each sphere can be calculated by taking the average of their initial charges:

Final charge = (Initial charge of sphere 1 + Initial charge of sphere 2) / 2

Substituting the values:

Final charge = (-5.5 nC + 1.5 nC) / 2

Calculating this, we find:

Final charge ≈ -2 nC

Therefore, the final charge of each sphere after contact will be approximately -2 nC [[3]].