Question

ВАГОНЕТКА МАССОЙ 200 КГ ДВИЖЕТСЯ РАВНОМЕРНО. С КАКОЙ СИЛОЙ РАБОЧИЙ ТОЛКАЕТ ВАГОНЕТКУ, ЕСЛИ КОЭФФИЦИЕНТ ТРЕНИЯ РАВЕН 0,6?

Answer 1

F=1200Н .............

Answer 2

Calculating the Force Required to Push the Wagon with a Coefficient of Friction of 0.6

To calculate the force required to push the wagon with a mass of 200 kg, moving uniformly, given a coefficient of friction of 0.6, we can use the formula for frictional force:

Frictional Force (F) = Coefficient of Friction (μ) × Normal Force (N)

Where the normal force (N) is equal to the weight of the object, which is the mass of the wagon multiplied by the acceleration due to gravity (9.8 m/s^2).

Using this information, we can calculate the force required to push the wagon.

The formula for the normal force (N) is: N = mass (m) × acceleration due to gravity (g)

Substituting the given values: N = 200 kg × 9.8 m/s^2

Now, we can calculate the normal force (N) and then use it to find the frictional force (F).

Calculation

1. Normal Force (N) - N = 200 kg × 9.8 m/s^2 - N = 1960 N

2. Frictional Force (F) - F = Coefficient of Friction (μ) × Normal Force (N) - F = 0.6 × 1960 N - F = 1176 N

Therefore, the force required to push the wagon, given a coefficient of friction of 0.6, is 1176 Newtons.

This calculation assumes a uniform surface and does not account for additional factors such as air resistance or incline.

If you have further questions or need additional assistance, feel free to ask!