Question

Мяч, брошенный горизонтально со скоростью 122 м/с, упал на Землю через 3 с. С какой высоты был брошен мяч? какова дальность его полёта?

Answer 1

122*3=366метров
а второй вопрос я не поняла

Answer 2

Рассмотрим систему
Ux=U0
Uy=-gt

x=U0T
y=gt^2/2

x- есть дальность полета
y - высота
Подставляем и получаем то что необходимо)

x=122*3=366м
y=10*9/2=45м

Answer 3

Calculation of the Initial Height and Range of the Ball

To calculate the initial height and range of the ball, we can use the equations of motion for horizontal projectile motion. In this case, the ball is thrown horizontally with a velocity of 122 m/s and falls to the ground after 3 seconds.

Let's start by finding the initial height (h) from which the ball was thrown. We can use the equation:

h = (1/2) * g * t^2,

where g is the acceleration due to gravity (approximately 9.8 m/s^2) and t is the time of flight (3 seconds).

Substituting the given values into the equation, we have:

h = (1/2) * 9.8 * (3^2) = 44.1 meters.

Therefore, the ball was thrown from a height of 44.1 meters.

Next, let's calculate the range of the ball, which is the horizontal distance traveled by the ball. The range (R) can be calculated using the equation:

R = v * t,

where v is the horizontal velocity of the ball (122 m/s) and t is the time of flight (3 seconds).

Substituting the given values into the equation, we have:

R = 122 * 3 = 366 meters.

Therefore, the range of the ball is 366 meters.

To summarize: - The ball was thrown from a height of 44.1 meters. - The range of the ball is 366 meters.

Please note that these calculations assume ideal conditions and neglect factors such as air resistance.