Question

Брусок массой 1 кг движется равноускоренно по горизонтальной поверхности под действием силы F=10 Н. Модуль силы трения, действующей на тело, равен 1 Н, а угол α=30 градусам. Чему равен коэффициент трения между бруском и плоскостью?

Answer 1

Сила, с которой движется брусок F=Fт-Fтр.
ma=Fт*cos(30)-M*m*g
a=(Fт*cos(30)-M*m*g)/m
a=(10H*(√3/2)-0.4*1кг*10Н/кг) /1кг.
a=4.66м/с^2

Answer 2

Calculating the Coefficient of Friction

To calculate the coefficient of friction between the block and the surface, we can use the formula:

μ = Ff / N

Where: - μ = coefficient of friction - Ff = force of friction - N = normal force

Calculating the Force of Friction (Ff)

The force of friction can be calculated using the formula:

Ff = μ * N

Where: - Ff = force of friction - μ = coefficient of friction - N = normal force

Calculating the Normal Force (N)

The normal force can be calculated using the formula:

N = mg

Where: - m = mass of the block - g = acceleration due to gravity (approximately 9.81 m/s^2)

Given Values

- Mass of the block (m) = 1 kg - Force applied (F) = 10 N - Angle (α) = 30 degrees - Coefficient of friction (μ) = ? - Acceleration due to gravity (g) = 9.81 m/s^2

Calculations

1. Calculating the Normal Force (N) - N = mg - N = 1 kg * 9.81 m/s^2 - N = 9.81 N

2. Calculating the Force of Friction (Ff) - Ff = μ * N - Ff = 1 N (given) - μ * N = 1 N - μ = Ff / N - μ = 1 N / 9.81 N - μ ≈ 0.102

Answer

The coefficient of friction between the block and the surface is approximately 0.102.