Question

СРОЧНО!!!!!!ДАЮ 80 БАЛЛОВ Прямой горизонтальный проводник длиной l=0.80 м и массой m=80 г движется с ускорением, направленным вертикально вниз, в однородном магнитном поле, линии индукции которого горизонтальны и перпендикулярно проводнику. Модуль индукции магнитного поля R=0.50 Тл. Определите силу тока в проводнике, если модуль ускорения проводника а=4м/с²

Answer 1

Согласно закону Ампера-Лапласа, сила, действующая на проводник с током в магнитном поле, равна F = B * I * l * sin(α), где B - магнитная индукция, I - сила тока в проводнике, l - длина проводника и α - угол между направлением тока и магнитным полем. В данном случае угол равен 90° и sin(α) = 1.

Так как проводник движется с ускорением а, то на него действует сила F = m * a. Заменив F в уравнении Ампера-Лапласа на m * a и решив уравнение относительно I, получим: I = (m * a) / (B * l).

Подставив известные значения в это уравнение, получим: I = (0.08 кг * 4 м/с²) / (0.5 Тл * 0.8 м) = 0.8 А.

Answer 2

Problem Analysis

We are given a horizontal conductor with a length of l = 0.80 m and a mass of m = 80 g. The conductor is moving with an acceleration directed vertically downwards in a uniform magnetic field with a magnetic induction of B = 0.50 T. We need to determine the current flowing through the conductor if the acceleration of the conductor is a = 4 m/s².

Solution

To solve this problem, we can use the equation that relates the force on a current-carrying conductor in a magnetic field to the current, magnetic field, length of the conductor, and the angle between the current and the magnetic field.

The equation is given by: F = BILsinθ

Where: - F is the force on the conductor - B is the magnetic field induction - I is the current flowing through the conductor - L is the length of the conductor - θ is the angle between the current and the magnetic field

In this case, the conductor is moving vertically downwards, so the angle θ between the current and the magnetic field is 90 degrees.

Since the conductor is accelerating, there must be a net force acting on it. This force is given by Newton's second law: F = ma

Where: - F is the net force on the conductor - m is the mass of the conductor - a is the acceleration of the conductor

By equating the two equations, we can solve for the current I.

Calculation

Substituting the given values into the equations, we have:

F = BILsinθ ma = BILsinθ

Rearranging the equation to solve for the current I, we get:

I = ma / (BLsinθ)

Substituting the given values: - m = 80 g = 0.08 kg - a = 4 m/s² - B = 0.50 T - L = 0.80 m - θ = 90 degrees

Converting the angle from degrees to radians: - θ = 90 degrees * (π/180) = π/2 radians

Substituting the values into the equation, we get:

I = (0.08 kg * 4 m/s²) / (0.50 T * 0.80 m * sin(π/2))

Calculating the value, we find:

I ≈ 0.64 A

Therefore, the current flowing through the conductor is approximately 0.64 Amperes.

Answer

The current flowing through the conductor is approximately 0.64 Amperes.