Question

Який ККД електродвигуна, що за 20 с піднімає вантаж масою 150 кг на висоту 12 м? Напруга в електричній мережі 380 В, сила струму че- рез двигун 4 А.

Answer 1

Ответ:

24 %

Объяснение:

t=20 с;

m=150 кг;

h=12 м;

U=380 В;

I=4 А;

KKД  ?   KKД=Aпoл/Aзаг=mgh/(U*I*t)=150*4*12/(380*4*20)=0.24=24 %

Answer 2

Efficiency of an Electric Motor

The efficiency of an electric motor can be calculated using the formula:

Efficiency = (Useful Output Power / Input Power) x 100%

To calculate the useful output power, we need to determine the work done by the motor in lifting the load. The work done is given by the formula:

Work = Force x Distance

In this case, the force is the weight of the load and the distance is the height the load is lifted.

Given: - Mass of the load (m) = 150 kg - Height lifted (h) = 12 m

To calculate the force, we can use the formula:

Force = Mass x Acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2.

To calculate the input power, we need to determine the electrical power consumed by the motor. The electrical power is given by the formula:

Power = Voltage x Current

Given: - Voltage (V) = 380 V - Current (I) = 4 A

Calculating the Force

Force = Mass x Acceleration due to gravity Force = 150 kg x 9.8 m/s^2

Calculating the Work

Work = Force x Distance Work = (150 kg x 9.8 m/s^2) x 12 m

Calculating the Input Power

Power = Voltage x Current Power = 380 V x 4 A

Calculating the Efficiency

Efficiency = (Useful Output Power / Input Power) x 100% Efficiency = (Work / Time) / (Power / Time) x 100%

Since the time is not provided in the question, we cannot calculate the efficiency without this information.

Please provide the time it takes for the motor to lift the load to the height of 12 m, and I will be able to calculate the efficiency of the electric motor.