Question

Трамвай розвиває швидкість 20м/с при силі тяги електродвигуна, яка дорівнює 1,2 кН. Напруга в контактній мережі 600В, сила струму в двигуні 50А. Визначити ККД електродвигуна трамвая. БУДЬ ЛАСКА НАДАЙТЕ ПОВНУ ВІДПОВІДЬ ​

Answer 1

Дано:

v=20м/с

F=1,2кН=1200Н

U=600B

I=50A

Знайти:

η-?

Fv=UIη

η=Fv/UI=1200*20/600*50=0,8=80%

Answer 2

To calculate the efficiency of the tram's electric motor, we need to know the power input and power output of the motor. The power input can be calculated using the formula:

Power Input (P_in) = Voltage (V) × Current (I)

Given that the voltage in the contact network is 600V and the current in the motor is 50A, we can calculate the power input as follows:

P_in = 600V × 50A

Now, we need to determine the power output of the motor. Power is defined as the rate at which work is done, and work is defined as force multiplied by distance. In this case, the force is the traction force of the electric motor, and the distance is the speed of the tram.

The power output can be calculated using the formula:

Power Output (P_out) = Traction Force (F) × Speed (v)

Given that the traction force of the electric motor is 1.2 kN (or 1200 N) and the speed of the tram is 20 m/s, we can calculate the power output as follows:

P_out = 1200 N × 20 m/s

Now that we have both the power input and power output, we can calculate the efficiency of the electric motor using the formula:

Efficiency (η) = (P_out / P_in) × 100%

Let's calculate the efficiency of the electric motor:

Calculation:

- Power Input (P_in) = 600V × 50A - Power Output (P_out) = 1200 N × 20 m/s - Efficiency (η) = (P_out / P_in) × 100%

Using the given values, we can now calculate the efficiency of the electric motor.