Question

Для рівномірного піднімання вантажу масою 800 кг по похилій площині, довжина якої 2 м і висота 0,5 м, потрібна сила 2500 Н. Визначити силу тертя. Вважати прискорення вільного падіння рівним » 10 м/с?

Answer 1

Відповідь:

500 H

Пояснення:

Answer 2

To determine the frictional force involved in lifting a load of 800 kg up a inclined plane with a length of 2 m and a height of 0.5 m, we can use the principles of physics. The force required to lift the load is given as 2500 N, and the acceleration due to gravity is 10 m/s².

Calculating the Work Done

The work done in lifting the load can be calculated using the formula:

Work = Force × Distance

In this case, the force is 2500 N and the distance is the vertical height of the inclined plane, which is 0.5 m. Therefore, the work done is:

Work = 2500 N × 0.5 m = 1250 J [[1]].

Calculating the Potential Energy

The work done in lifting the load is equal to the change in potential energy of the load. The potential energy can be calculated using the formula:

Potential Energy = Mass × Gravity × Height

In this case, the mass is 800 kg, the acceleration due to gravity is 10 m/s², and the height is 0.5 m. Therefore, the potential energy is:

Potential Energy = 800 kg × 10 m/s² × 0.5 m = 4000 J [[2]].

Calculating the Frictional Force

The frictional force can be calculated by subtracting the work done from the potential energy:

Frictional Force = Potential Energy - Work

Substituting the values we calculated earlier:

Frictional Force = 4000 J - 1250 J = 2750 J.

Therefore, the frictional force involved in lifting the load is 2750 J.

Please note that the unit of force is Joules (J), not Newtons (N). The frictional force is the difference between the potential energy and the work done, and it represents the energy lost due to friction during the lifting process.

I hope this helps! Let me know if you have any further questions.