Question

Чтобы охладить выточенную из меди деталь, имеющую температуру 100°С, ее погрузили в 420г воды с температурой 15°С. Определите массу детали, если известно, что в процессе теплообмена вода нагрелась до 18°С

Answer 1

Q=cmT

Вода получила столько темплоты, сколько потеряла мед. деталь

Поэтому:

$Q_{1}=Q_{2}$

$c_{1}m_{1}T_{1}=c_{2}m_{2}T_{2}$

Теплоемкости. Воды - 4200 Дж/(кг*С) - $c_{1}$

                        Меди - 390 Дж/(кг*С) - $c_{2}$

Температуры. Изменение температуры воды $T_{1}$=18-15=3

                      Изменение температуры меди $T_{2}$=100-18=82

$m_{1}$=0.42кг

$m_{2}=\frac{c_{1}m_{1}T_{1}}{c_{2}T_{2}}$

 

Answer 2

Calculation of the Mass of the Copper Part

To determine the mass of the copper part, we can use the principle of heat exchange. The heat gained by the water is equal to the heat lost by the copper part. The formula for heat exchange is:

Q1 = Q2

Where: - Q1 is the heat gained by the water - Q2 is the heat lost by the copper part

The formula for heat exchange is:

Q1 = m * (T - t)

Where: - m is the mass of the water - T is the final temperature of the water - t is the initial temperature of the water

The formula for heat exchange for the copper part is:

Q2 = M * (t0 - t)

Where: - M is the mass of the copper part - t0 is the initial temperature of the copper part - t is the final temperature of the copper part

Since Q1 = Q2, we can equate the two formulas:

m * (T - t) = M * (t0 - t)

We are given the following values: - m = 420 g (mass of water) - T = 18°C (final temperature of water) - t0 = 100°C (initial temperature of copper part) - t = 15°C (final temperature of copper part)

Substituting these values into the equation, we can solve for M:

420 * (18 - 15) = M * (100 - 15)

Simplifying the equation:

1260 = 85M

Solving for M:

M = 1260 / 85 = 14.82 g

Therefore, the mass of the copper part is approximately 14.82 grams.