Question

Тепловой двигатель совершает за цикл работу 100 Дж. Какое количество теплоты получило при этом от нагрева тела, если КПД двигателя 20% ?

Answer 1

работа по ф-ле  А=Qн-Qх(1)

КПД по ф-ле  ή=(Qн-Qх)/Qн (2)

подставим (1) в (2)

ή=А/Qн

Qн=А/ή=100 Дж/0.20=500 Дж

Answer 2

Calculation of Heat Received by the Engine

To calculate the amount of heat received by the engine, we can use the formula for thermal efficiency (η) of the engine:

η = (Work output / Heat input) * 100%

Given that the work output of the engine is 100 J (Joules) and the thermal efficiency (η) is 20%, we can rearrange the formula to solve for the heat input:

Heat input = (Work output / η) * 100%

Substituting the given values:

Heat input = (100 J / 0.20) * 100% = 500 J

Therefore, the amount of heat received by the engine from the heat source is 500 Joules