Question

объём газа увеличивается с 450 л до 600 л и работал на 400 дж каково давление газа если оно не меняется во время работы​

Answer 1

Ответ:

3667 Па

Объяснение:

V1=0.45 м³    V2=0.6 м³     A=400 Дж    p=?

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A=p*(V2-V1)

p=A/(V2-V1)=400/(0.6-0.45)=2667 Па

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Answer 2

Calculation of Gas Pressure

To calculate the gas pressure, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of gas - R is the ideal gas constant - T is the temperature of the gas

In this case, we are given that the volume of the gas increases from 450 L to 600 L, and the gas does work of 400 J. We need to find the pressure of the gas if it remains constant during the work.

Since the gas does work, we can assume that the process is not isothermal (temperature remains constant) but adiabatic (no heat exchange). In an adiabatic process, the relationship between pressure and volume is given by:

P1 * V1^γ = P2 * V2^γ

Where: - P1 and P2 are the initial and final pressures, respectively - V1 and V2 are the initial and final volumes, respectively - γ is the heat capacity ratio of the gas (specific heat capacity at constant pressure divided by specific heat capacity at constant volume)

In this case, since the pressure remains constant, we can simplify the equation to:

V1^γ = V2^γ

Now, let's substitute the given values into the equation and solve for the initial pressure (P1):

450^γ = 600^γ

To solve this equation, we need to know the value of γ, which depends on the specific gas. Unfortunately, the search results provided by You.com do not contain the necessary information to determine the value of γ for the gas in question. Therefore, we cannot provide a specific numerical answer to the question without this information.

If you have any additional information or if there is anything else I can help you with, please let me know!