Question

3. Вечоріло. Втомлений рибак Абдула присів на березі річки спочити. Бачить. пливс якийсь предмет, майже повністю занурений у воду. Абдула зайшов у рiчку та витягнув його. Дивиться, а це старовинний, герметично закритий глечик. Вiдкрив Аодула глечика, а з нього висипалося 147 однакових золотих монет. Монети Абдула сховав у кишеню, а глечик герметично закрив корком і кинув назад у рытку. Поплив глечик за течею річки, виступаючи на третину над водою. Вважаючи, що об см глечика становить 2 л. оцініть масу однісï золотої монети ​

Answer 1

According to the search results, the problem you provided seems to be a math problem involving the mass of a gold coin. Let's break it down step by step.

Given Information:

- Abdul, a tired fisherman, found a submerged object in the river. - He went into the river and pulled out a tightly sealed jug. - Abdul opened the jug and found 147 identical gold coins inside. - He put the coins in his pocket and closed the jug tightly with a cork. - Abdul threw the jug back into the river, and it floated with one-third of it above the water. - The volume of the jug is 2 liters.

Calculating the Mass of a Gold Coin:

To calculate the mass of a single gold coin, we need to make some assumptions and use the given information.

1. Assume that the jug is completely filled with water when it is submerged in the river. 2. Assume that the density of water is 1 gram per milliliter (g/mL). 3. Assume that the jug is completely filled with gold coins when it is out of the water.

Using these assumptions, we can calculate the mass of a gold coin.

Calculation:

1. The volume of the jug is given as 2 liters, which is equal to 2000 milliliters (mL). 2. Since the jug floats with one-third of it above the water, the volume of the submerged part is 2/3 of the total volume, which is (2/3) * 2000 mL = 1333.33 mL. 3. The mass of the water displaced by the submerged part of the jug is equal to the mass of the jug and the gold coins combined. 4. The mass of the jug can be calculated by multiplying the volume of the submerged part by the density of water: 1333.33 mL * 1 g/mL = 1333.33 grams (g). 5. Since the jug is tightly sealed, the mass of the gold coins is equal to the mass of the jug and the gold coins combined minus the mass of the jug: 1333.33 g - mass of the jug. 6. The mass of a single gold coin can be calculated by dividing the total mass of the gold coins by the number of coins: (1333.33 g - mass of the jug) / 147.

Unfortunately, the search results did not provide the mass of the jug or any additional information needed to calculate the mass of a single gold coin. Therefore, it is not possible to determine the mass of a single gold coin based on the given information.

Please note that the calculations provided above are based on the assumptions made and may not reflect the actual situation.