Question

Поршень гидравлического преса площадью 180 см квадратных действует сила 180кН площадь малого поршня 5см квадратных .С какой силой действует меньший поршень на жидкость под поршнем

Answer 1

Дано:
S1 = 180 см²
F1 = 180 000 Н
S2 = 5 см²
Найти: F2 - ?
Решение:
F1/S1 = F2/S2
F1/F2 = S1/S2
F1/F2 = 180 см²/5 см² = 36
F2 = F1/36 = 180 000 Н/36 = 5 000 Н

Answer 2

Hydraulic Press Force Calculation

To calculate the force exerted by the smaller piston on the fluid beneath it, we can use the principle of Pascal's law, which states that the pressure exerted at any point of a confined fluid is transmitted undiminished in all directions throughout the fluid.

Given: - Area of the larger piston (A1) = 180 cm^2 - Force exerted on the larger piston (F1) = 180 kN - Area of the smaller piston (A2) = 5 cm^2 - Force exerted by the smaller piston (F2) = ?

Calculation

According to Pascal's law, the pressure exerted by the larger piston is transmitted undiminished to the smaller piston. The formula to calculate the force exerted by the smaller piston is:

F2 = F1 * (A2 / A1)

Substituting the given values: F2 = 180 kN * (5 cm^2 / 180 cm^2)

Result

Calculating the above expression gives us the force exerted by the smaller piston on the fluid beneath it.

F2 = 5 kN

Therefore, the force exerted by the smaller piston on the fluid beneath it is 5 kN.