Question

В однородное магнитное поле с индукцией 1,3 тл перпендикулярно линиям магнитной индукции поместили проводник длиной 20 см , по которому протекаеть электр. Ток. Напряжение в клнцах проводника 12В, сопротивление проводника 2,4 Ом. Опредедите силу, с которой магнитное пое действует на проводник с током.

Answer 1

Α=90°                     сила Ампера:
B=1,3 Тл                   F=BILsin90°=BIL*1=BIL;  I=U/R=12/2,4=5 A;
L=20 см=0,2 м         F=1,3*5*0,2=1,3 H;
U=12 B                    Ответ: F=1,3 H. 
R=2,4 Ом
___________
F-?

Answer 2

Calculating the Force on a Conductor in a Magnetic Field

To calculate the force exerted on a conductor carrying a current in a magnetic field, we can use the formula:

F = BIL

Where: - F is the force in newtons (N) - B is the magnetic field strength in teslas (T) - I is the current in amperes (A) - L is the length of the conductor in meters (m)

Given: - Magnetic field strength (B) = 1.3 T - Length of the conductor (L) = 20 cm = 0.2 m - Current (I) = V/R, where V is the voltage and R is the resistance

Calculating the Current

First, let's calculate the current (I) using the given voltage (V) and resistance (R):

I = V / R

Given: - Voltage (V) = 12 V - Resistance (R) = 2.4 Ω

I = 12 V / 2.4 Ω = 5 A

So, the current flowing through the conductor is 5 A.

Calculating the Force

Now, we can calculate the force (F) exerted on the conductor in the magnetic field using the formula:

F = BIL

Substitute the given values: - B = 1.3 T - I = 5 A - L = 0.2 m

F = (1.3 T) * (5 A) * (0.2 m) F = 1.3 * 5 * 0.2 F = 1.3 N

So, the force with which the magnetic field acts on the conductor carrying the current is 1.3 N.