Question

СРОЧНО ПОЖАЛУЙСТА!!! Газовый баллон был заполнен 7 кг пропана. Если объем баллона составлял 50 литров, а давление составляло 8 МПа, какой была температура газа в то время?​

Answer 1

Ответ:

303 K   (30°С)

Объяснение:

M=0.044 кг/моль     m=7 кг    V=0.05 м³    p=8*10^6 Па   T=?

===

p*V=(m/M)*R*T

T=p*V*M/(m*R)=8*10^6*0.05*0.044/(7*8.31)≈303 K   (30°C)

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Answer 2

Calculation of Gas Temperature

To calculate the temperature of the gas in the cylinder, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (in Pascals) - V is the volume of the gas (in cubic meters) - n is the number of moles of gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (in Kelvin)

In this case, we have the following information: - The volume of the cylinder is 50 liters, which is equivalent to 0.05 cubic meters. - The pressure of the gas is 8 MPa, which is equivalent to 8,000,000 Pascals. - The mass of the propane gas is 7 kg.

To calculate the number of moles of gas, we need to know the molar mass of propane. The molar mass of propane is approximately 44.1 g/mol.

Let's calculate the number of moles of propane gas first:

moles = mass / molar mass

moles = 7 kg / (44.1 g/mol)

moles = 7,000 g / 44.1 g/mol

moles ≈ 158.005 moles

Now, we can rearrange the ideal gas law equation to solve for temperature:

T = (PV) / (nR)

T = (8,000,000 Pa) * (0.05 m^3) / (158.005 moles * 8.314 J/(mol·K))

T ≈ 60,606.06 K

Therefore, the temperature of the gas in the cylinder at that time was approximately 60,606.06 Kelvin.

Please note that this calculation assumes ideal gas behavior and does not take into account any heat transfer or other factors that may affect the temperature of the gas.