Question

Волюмометр объемом 4 л, давление воздуха в котором равнялось 140 кПа, подсоединили к сосуду, в котором практически не было воздуха. В результате давление в приборе упало до 80 кПа. Каков был объем исследуемого сосуда? Ответ: 3 литра

Answer 1

Ответ:

p1=140 кПа

V1=x л

V2=x+6 л

р2=100 кПа

-------------

х - ?

уравнение Менделеева-Клапейрона

p1V1 =vRT   состояние 1

p2V2 =vRT   состояние 2

правая часть уравнений (1) (2)  не меняется , т к по условию Процесс изотермический.

приравняем левую чать

p1V1 =p2V2

V1 = V2 * p2/p1

x = (x+6) * 100/140 = (x+6)*5/7

7x =5(x+6)

2x =30

x=15 л

Объяснение:

Answer 2

Calculation of the Volume of the Vessel

To calculate the volume of the vessel, we can use the ideal gas law equation, which states that the product of pressure and volume is proportional to the product of the number of moles of gas and the gas constant, at a given temperature. The equation can be written as:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of gas - R is the gas constant - T is the temperature of the gas

In this case, we have the initial pressure (140 kPa) and volume (4 liters) of the vessel, and the final pressure (80 kPa) after connecting it to another vessel with almost no air. We need to find the volume of the vessel after the connection.

To solve for the volume of the vessel, we can rearrange the ideal gas law equation as follows:

V = (nRT) / P

Since the number of moles of gas and the gas constant remain constant, we can simplify the equation to:

V = k / P

Where k is a constant.

To find the value of k, we can use the initial conditions of the vessel, where P = 140 kPa and V = 4 liters:

k = PV = (140 kPa) * (4 liters) = 560 kPa*liters

Now, we can use the value of k and the final pressure (80 kPa) to calculate the volume of the vessel:

V = k / P = (560 kPa*liters) / (80 kPa) = 7 liters

Therefore, the volume of the vessel is 7 liters.