Question

Два шара массой 2кг и 1кг движутся навстречу друг другу со скоростью 7м\с и 8м\с .Какова будет скорость шаров после неупрогого соударения.

Answer 1

Закон сохранения импульса
m1V1-m2V2=(m1+m2)V
V=$\frac{m1V1-m2V2}{m1+m2}$
при счете у тебя получиться 
V=2м/с
и направлена в сторону движения 1 шара

Answer 2

Calculation of the velocity of the balls after an inelastic collision

To calculate the velocity of the balls after an inelastic collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Therefore, the momentum of the first ball before the collision is given by the product of its mass (2 kg) and velocity (7 m/s), and the momentum of the second ball before the collision is given by the product of its mass (1 kg) and velocity (8 m/s).

Using the conservation of momentum, we can set up the following equation:

(m1 * V1) + (m2 * V2) = (m1 + m2) * V

Where: - m1 and m2 are the masses of the first and second balls, respectively. - V1 and V2 are the velocities of the first and second balls before the collision, respectively. - V is the velocity of the balls after the collision.

Substituting the given values into the equation, we have:

(2 kg * 7 m/s) + (1 kg * 8 m/s) = (2 kg + 1 kg) * V

Simplifying the equation, we get:

14 kg m/s + 8 kg m/s = 3 kg * V

22 kg m/s = 3 kg * V

Dividing both sides of the equation by 3 kg, we find:

V = 22 kg m/s / 3 kg

V ≈ 7.33 m/s

Therefore, the velocity of the balls after the inelastic collision will be approximately 7.33 m/s.