Question

К цепи, состоящей из трех резисторов с сопротивлениями R1=10Ом,R2=30Ом,R3=20Ом,приложено напряжение 200В. Определить силу тока в каждом резисторе, сопротивление цепи, напряжение на первом и на втором резисторе. Определить потребляемую цепью мощьность и расход энергии за 6 часов работы.

Answer 1

R=R1+R2+R3
R=100Ом+300Ом+200Ом=600 Ом
J=U/R
J=200В/600 Ом=0,3А при последоват. одинакова на всех резисторах
U1=J*R1=0,3А*100 Ом=30В
U2=J*R2=0,3А*300 Ом=90В
Р=J*U=0,3А*200В=60Вт
A=P*t=60Вт*6ч=360 Вт ч

Answer 2

Calculation of Current and Resistance

To determine the current flowing through each resistor, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R).

Given the following resistances and voltage: - R1 = 10Ω - R2 = 30Ω - R3 = 20Ω - Voltage (V) = 200V

We can calculate the current (I) in each resistor as follows:

- Current in R1 (I1) = V / R1 = 200V / 10Ω = 20A- Current in R2 (I2) = V / R2 = 200V / 30Ω = 6.67A- Current in R3 (I3) = V / R3 = 200V / 20Ω = 10A To determine the total resistance (Rt) of the circuit, we can use the formula for resistors in series, which states that the total resistance is the sum of the individual resistances:

- Rt = R1 + R2 + R3 = 10Ω + 30Ω + 20Ω = 60Ω

Voltage across Resistor 1 and Resistor 2

To determine the voltage across each resistor, we can use Ohm's Law again. The voltage across a resistor is equal to the current flowing through it multiplied by its resistance.

- Voltage across R1 (V1) = I1 * R1 = 20A * 10Ω = 200V- Voltage across R2 (V2) = I2 * R2 = 6.67A * 30Ω = 200V

Power and Energy Consumption

To calculate the power consumed by the circuit, we can use the formula P = VI, where P is power, V is voltage, and I is current.

- Power consumed by the circuit (P) = V * (I1 + I2 + I3) = 200V * (20A + 6.67A + 10A) = 73,400W or 73.4kW To determine the energy consumption over a period of 6 hours, we can use the formula E = Pt, where E is energy, P is power, and t is time.

- Energy consumed by the circuit (E) = P * t = 73,400W * 6 hours = 440,400Wh or 440.4kWh Please note that these calculations assume an ideal circuit with no losses or other factors that may affect the actual values.

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