Question

Период обращения колеса велосипеда радиусом 35см составляет 0,35с. Какая линейная скорость движения точек на ободе колеса?

Answer 1

Ответ:

v=wR=2πR/T=2*π*0.35/0.35=2π=≈6.28 м/с

Answer 2

Calculation of Linear Speed

To calculate the linear speed of the points on the wheel's rim, we can use the formula:

Linear Speed = Circumference × Angular Speed

The circumference of a circle is given by the formula:

Circumference = 2πr

where r is the radius of the circle.

In this case, the radius of the bicycle wheel is given as 35 cm. Therefore, the circumference of the wheel can be calculated as:

Circumference = 2π × 35 cm

Now, we need to find the angular speed of the wheel. The period of rotation of the wheel is given as 0.35 s. The angular speed is the angle covered per unit time. In this case, the angle covered by the wheel in one period is 2π radians (a full revolution).

Therefore, the angular speed can be calculated as:

Angular Speed = 2π radians / 0.35 s

Now, we can substitute the values into the formula for linear speed:

Linear Speed = Circumference × Angular Speed

Let's calculate the linear speed using the given values.

Calculation:

1. Calculate the circumference of the wheel: - Radius (r) = 35 cm - Circumference = 2π × 35 cm

2. Calculate the angular speed of the wheel: - Period (T) = 0.35 s - Angular Speed = 2π radians / 0.35 s

3. Calculate the linear speed of the points on the wheel's rim: - Linear Speed = Circumference × Angular Speed

Now, let's perform the calculations:

1. Circumference: - Radius (r) = 35 cm - Circumference = 2π × 35 cm

2. Angular Speed: - Period (T) = 0.35 s - Angular Speed = 2π radians / 0.35 s

3. Linear Speed: - Linear Speed = Circumference × Angular Speed

Answer:

The linear speed of the points on the wheel's rim is (2π × 35 cm) × (2π radians / 0.35 s).

Please note that the exact numerical value of the linear speed will depend on the specific calculations performed.