Question

Сила тяжести чугунного шара объемом 125см в кубе имеет величину 8 Н. Какой это шар – сплошной или полый?

Answer 1

V = 125 см³.
ρ = 7800 кг/м³;
решение:
F = mg;

m = ρV;

F = ρgV(1);

V(1) = F/ρg = 8/(7800*10) = 8/78000 = 0,0001025 м³ = 125 см³.

V = V(1) → полости нет.

Answer 2

The force of gravity on a solid iron sphere with a volume of 125 cm³ is 8 N. Is this sphere solid or hollow?

To determine whether the iron sphere is solid or hollow, we need to consider its density. The density of an object is defined as its mass per unit volume. In this case, we are given the force of gravity acting on the sphere, but we need additional information to determine its density.

Unfortunately, the search results provided do not contain the necessary information to directly answer the question. However, we can make some general observations based on the given information.

If the sphere is solid, its density would be determined by dividing its mass by its volume. The force of gravity acting on the sphere is related to its mass through the equation F = mg, where F is the force of gravity, m is the mass, and g is the acceleration due to gravity. Since we are given the force of gravity (8 N), we can calculate the mass of the sphere using the equation m = F/g.

However, without the mass of the sphere, we cannot determine its density or conclusively determine whether it is solid or hollow. Therefore, based on the information provided, we cannot determine whether the iron sphere is solid or hollow.

If you have any additional information or if there is anything else I can assist you with, please let me know!