Question

Тягарець масою 5 кг, підвішений до динамометра, піднімають вертикально вгору з прискоренням 7 м/с². Визначте, з яким прискоренням його потім опускають, якщо різниця показань динамометра становить 50 Н. срочно, з розв'язком.​

Answer 1

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Answer 2

To determine the acceleration at which the weight is subsequently lowered, we need to consider the forces acting on the weight. When the weight is lifted vertically upwards with an acceleration of 7 m/s², the net force acting on it is the difference between the force of gravity and the force measured by the dynamometer. #### Given: - Mass of the weight (m) = 5 kg - Acceleration while lifting (a₁) = 7 m/s² - Difference in dynamometer readings (ΔF) = 50 N #### Solution: 1. Calculate the force of gravity acting on the weight while lifting: - Force of gravity (Fg) = mass (m) × acceleration due to gravity (g) - Assuming the acceleration due to gravity is approximately 9.8 m/s², we have: - Fg = 5 kg × 9.8 m/s² = 49 N 2. Calculate the net force acting on the weight while lifting: - Net force (F_net) = Force of gravity (Fg) - Difference in dynamometer readings (ΔF) - F_net = 49 N - 50 N = -1 N (negative sign indicates the force is acting downwards) 3. Calculate the acceleration while lowering the weight: - Net force (F_net) = mass (m) × acceleration (a₂) - Rearranging the equation, we have: - a₂ = F_net / m - a₂ = -1 N / 5 kg = -0.2 m/s² #### Answer: The weight is subsequently lowered with an acceleration of **-0.2 m/s²**. The negative sign indicates that the weight is being lowered in the opposite direction of the initial upward acceleration.