Question

30 баллов!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Над первоначально покоившимся в инерциальной системе отсчёта точечным телом массой 2 кг сила совершила работу 100 Дж. Определите модуль конечной скорости этого тела.

Answer 1

Можно учесть, что работа в данной задаче будет равно кинетической энергии, тогда
E=mV^2/2
100*2дж=2кг*V^2
отсюда, V^2=100
V=10 м/c

Answer 2

To determine the final velocity of an object, we need to use the work-energy principle. The work done on an object is equal to the change in its kinetic energy. In this case, the work done on the object is 100 J, and we need to find the final velocity. #### Work-Energy Principle: According to the work-energy principle, the work done on an object is equal to the change in its kinetic energy. Mathematically, it can be expressed as: **Work = Change in Kinetic Energy** #### Calculation: Given: - Mass of the object (m) = 2 kg - Work done on the object (W) = 100 J We can use the equation for work to find the change in kinetic energy: **W = ΔKE** Since the object starts from rest, its initial kinetic energy is zero. Therefore, the change in kinetic energy is equal to the final kinetic energy. **W = KE_final - KE_initial** Substituting the given values: **100 J = KE_final - 0** Therefore, the final kinetic energy (KE_final) is equal to 100 J. The kinetic energy of an object can be calculated using the equation: **KE = (1/2) * m * v^2** Where: - KE is the kinetic energy - m is the mass of the object - v is the velocity of the object Rearranging the equation, we can solve for the velocity: **v = sqrt((2 * KE) / m)** Substituting the values: **v = sqrt((2 * 100 J) / 2 kg)** Simplifying the equation: **v = sqrt(100 J / 2 kg)** **v = sqrt(50 m^2/s^2)** **v = 7.07 m/s** Therefore, the module of the final velocity of the object is **7.07 m/s**. [[SOURCE 1]]