Question

Камень массой 0,2 кг падает с обрыва и летит до Земли ровно 2 секунды с ускорением g. Чему равно изменение импульса камня, если его начальная скорость была равна 0.

Answer 1

Дано Vo=0    ΔP- ?


V=gt

ΔP=mV=mgt=0,2*10*2=4 кг*м\с

Answer 2

Calculating Change in Momentum of the Stone

To calculate the change in momentum of the stone, we can use the formula for momentum, which is given by:

Momentum (p) = mass (m) × velocity (v)

Given that the stone has a mass of 0.2 kg and falls for 2 seconds with an initial velocity of 0, we can calculate the change in momentum using the following steps:

1. First, we need to find the final velocity (v) of the stone when it reaches the ground. 2. Then, we can use the formula for momentum to calculate the change in momentum.

Let's proceed with the calculations.

Finding the Final Velocity (v) of the Stone

The final velocity (v) of the stone can be calculated using the formula for uniformly accelerated motion:

v = u + at

Where: - v = final velocity - u = initial velocity (which is 0 in this case) - a = acceleration due to gravity (g) - t = time taken (which is 2 seconds in this case)

Substituting the given values: v = 0 + g × t

Calculating Acceleration due to Gravity (g)

The acceleration due to gravity (g) is approximately 9.81 m/s^2 on the surface of the Earth.

Substituting Values to Find Final Velocity (v)

Substituting the value of time (t = 2 seconds) and acceleration due to gravity (g ≈ 9.81 m/s^2) into the formula, we can find the final velocity (v) of the stone.

Calculating Change in Momentum

Once we have the final velocity (v), we can use the formula for momentum to calculate the change in momentum of the stone.

I will now proceed with the calculations and provide the final result.