
Луч света переходит из воды (n=1,33 )в стекло (n=1,6 )Угол падения равен 55 градусов.Найдите угол
отклонения луча от первоначального.Сделайте чертеж

Ответы на вопрос

Ответ:
на рисунке показано решение этой задачи и её чертёж))
Объяснение:
Рисунок




Calculation of the Angle of Deviation
To find the angle of deviation when light passes from water (n=1.33) to glass (n=1.6) with an incident angle of 55 degrees, we can use Snell's law. Snell's law states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the velocities of light in the two media.
The formula for Snell's law is:
n1 * sin(θ1) = n2 * sin(θ2)
Where: - n1 is the refractive index of the first medium (water in this case) - θ1 is the angle of incidence - n2 is the refractive index of the second medium (glass in this case) - θ2 is the angle of refraction (which we need to find)
Let's calculate the angle of refraction using the given values:
n1 = 1.33 (refractive index of water) n2 = 1.6 (refractive index of glass) θ1 = 55 degrees (angle of incidence)
Using Snell's law, we can rearrange the equation to solve for θ2:
θ2 = arcsin((n1 * sin(θ1)) / n2)
Substituting the given values:
θ2 = arcsin((1.33 * sin(55)) / 1.6)
Calculating this using a calculator or a programming language, we find that the angle of refraction (θ2) is approximately 38.7 degrees.
Therefore, the angle of deviation (the angle by which the light ray is bent) from the initial direction is the difference between the angle of incidence and the angle of refraction:
Angle of deviation = θ1 - θ2 = 55 - 38.7 = 16.3 degrees.
Diagram
Here is a diagram illustrating the situation:
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