Question

Емкость конденсатора 58мкФ. Какой заряд он накопит при его подключении к источнику тока с напряжением 50B?

Answer 1

Дано:
C = 56 мкФ = 58×10⁻⁶Ф
U = 50 В
Найти:
q =?
Решение:
C = q/U
q = CU = 58×10⁻⁶Ф × 50 В = 2,9 ×10⁻³Кл
Ответ: 2,9 ×10⁻³Кл

Answer 2

Дано:
C=58мкФ=
=5,8×10Ф,U=50B
найти q
Решение:
q=CU=5,8×10Ф×50B=2,9×10Кл=2,9мКл

Answer 3

Calculation of Charge Accumulated by a Capacitor

To calculate the charge accumulated by a capacitor when it is connected to a current source with a voltage of 50V, we need to use the formula:

Q = C * V

Where: - Q is the charge accumulated by the capacitor, - C is the capacitance of the capacitor, and - V is the voltage across the capacitor.

In this case, the capacitance of the capacitor is given as 58μF (microfarads) and the voltage across the capacitor is 50V.

Substituting these values into the formula, we get:

Q = 58μF * 50V

To perform the calculation, we need to convert the capacitance from microfarads to farads. Since 1 microfarad is equal to 1 × 10^-6 farads, we have:

Q = 58 × 10^-6 F * 50V

Simplifying the expression, we get:

Q = 2.9 × 10^-4 C

Therefore, the capacitor will accumulate a charge of 2.9 × 10^-4 coulombs when connected to a current source with a voltage of 50V.