Question

T1=0.25ч s1=15км t2=5ч s2=400км t3=05ч s3=30км vср=?

Answer 1

(15+400+30) : (5+0,25+0,5) = 445 : 5,75 = 77,3 км/ч
округлено.

Answer 2

Vср = Sвесь\Tвсё; (15+400+30)\(0.25+5+0.5)≈77 км\ч

Answer 3

To find the average velocity (vср) for the entire trip, you can use the following formula:

$vср = \frac{Σs}{Σt}$

Where:

• $Σs$ is the total distance traveled, which is the sum of $s1$, $s2$, and $s3$.
• $Σt$ is the total time taken, which is the sum of $t1$, $t2$, and $t3$.

Let's calculate $Σs$ and $Σt$ first:

$Σs = s1 + s2 + s3 = 15км + 400км + 30км = 445км$

$Σt = t1 + t2 + t3 = 0.25ч + 5ч + 0.05ч = 5.3ч$

Now, you can calculate the average velocity:

$vср = \frac{Σs}{Σt} = \frac{445км}{5.3ч} \approx 83.96 \frac{км}{ч}$

So, the average velocity for the entire trip is approximately 83.96 км/ч.