Question

Чему равна архимедова сила, действующая в воде на тело объёмом 0,03 м³ из стекла?

Answer 1

Архимедова (выталкивающая) сила находится по формуле F=pgV, где р-плотность жидкости (у воды при 4°С плотность 1000 кг/м³), g-ускорение свободного падения (≈10 Н/кг), V-объём тела. Подставим: F=1000x10x0.03=300 Н
Ответ: 300 Н

Answer 2

Archimedes' Force on a Body in Water

The Archimedes' force acting on a body submerged in water is equal to the weight of the water displaced by the body. This force can be calculated using the formula:

F = ρ * g * V

Where: - F is the Archimedes' force, - ρ is the density of the fluid (in this case, water), - g is the acceleration due to gravity, and - V is the volume of the fluid displaced by the body.

Given that the volume of the body in question is 0.03 m³ and it is made of glass, we can calculate the Archimedes' force using the density of water and the acceleration due to gravity.

Calculation of Archimedes' Force

Using the formula F = ρ * g * V, and considering the density of water (ρ) to be approximately 1000 kg/m³ and the acceleration due to gravity (g) to be approximately 9.81 m/s², we can calculate the Archimedes' force.

F = 1000 kg/m³ * 9.81 m/s² * 0.03 m³

The Archimedes' force acting on the body with a volume of 0.03 m³ in water can be calculated using the above formula.

Result

The Archimedes' force acting on the body with a volume of 0.03 m³ in water is approximately 29.43 N.

This calculation is based on the principles of Archimedes' principle and the properties of water as the surrounding fluid.