Question

Напишите пожалуйста полное решение! Льдина, имеющая форму призмы, плавает в воде, высовываясь наружу на 2 см. Какова масса льдины, если площадь ее основания равна 2000 см2? Плотность льда равна 920 кг/м3. Объем призмы считается по формуле V = Sоснования • h.

Answer 1

S=2000cм^2=0,2м^2
m=pV
V=S×h=0,2м^2×0,02м=0,04м^3
m=920кг/м^3×0,04м^3=36,8кг

Answer 2

S = 2000 см2 = 0,2 м²
p = 920 кг/м³
h = 2 см = 0,2 м

m - ?

Решение:
V = S × h, m = pV => m = pSh,
m = 920 × 0,2 × 0,2 = 184 × 0,2 = 36,8 (кг)

Ответ: m = 36,8 кг.

Answer 3

Calculation of the Mass of the Iceberg

To calculate the mass of the iceberg, we need to find its volume first. The volume of a prism can be calculated using the formula V = S * h, where V is the volume, S is the area of the base, and h is the height.

Given that the iceberg has the shape of a prism and protrudes 2 cm above the water, we can calculate its volume as follows:

V = S * h

Where: - S is the area of the base = 2000 cm^2 - h is the height = 2 cm

Plugging in the values, we get:

V = 2000 cm^2 * 2 cm = 4000 cm^3

Now, we need to convert the volume from cm^3 to m^3 to match the density unit. Since 1 m = 100 cm, 1 m^3 = (100 cm)^3 = 1,000,000 cm^3. Therefore, the volume in m^3 is:

V = 4000 cm^3 / 1,000,000 = 0.004 m^3

The density of ice is given as 920 kg/m^3. To find the mass of the iceberg, we can use the formula:

mass = density * volume

Plugging in the values, we get:

mass = 920 kg/m^3 * 0.004 m^3 = 3.68 kg

Therefore, the mass of the iceberg is approximately 3.68 kg.

Please note that the calculation assumes the iceberg is made entirely of ice and has a uniform density throughout.