Question

Бак, имеющий форму куба, объемом 8 куб.м. заполнен нефтью. Определите силу давления нефти на дно бака. (Плотность нефти 800 кг/куб.м)

Answer 1

Дано:
V = 8 м³;
ρ = 800 кг/м³;
g = 10 м/с²;
Fд — ?

Решение:
Fд = mg = ρVg;
Fд = 800*8*10 = 64000 (H).
64000 H = 64 кН.

Ответ: 64 кН.

Answer 2

Calculating Pressure Exerted by Oil in a Cubic Tank

To calculate the pressure exerted by the oil on the bottom of the tank, we can use the formula for pressure:

Pressure (P) = Force (F) / Area (A)

The force exerted by the oil can be calculated using the formula:

Force (F) = Weight (W) = Mass (m) * Acceleration due to gravity (g)

The mass of the oil can be calculated using the formula:

Mass (m) = Volume (V) * Density (ρ)

Given: - Volume (V) = 8 cubic meters - Density of oil (ρ) = 800 kg/cubic meter - Acceleration due to gravity (g) = 9.8 m/s^2 (standard value)

Calculation

1. Calculate the mass of the oil: - Mass (m) = Volume (V) * Density (ρ) - Mass (m) = 8 cubic meters * 800 kg/cubic meter - Mass (m) = 6400 kg

2. Calculate the force exerted by the oil: - Force (F) = Weight (W) = Mass (m) * Acceleration due to gravity (g) - Force (F) = 6400 kg * 9.8 m/s^2 - Force (F) = 62720 N

3. Calculate the pressure exerted by the oil: - Pressure (P) = Force (F) / Area (A) - As the tank has a square base, the area of the base is equal to the area of one of the sides squared. - Area (A) = Side length * Side length - Given that the tank has a cubic shape, the side length can be calculated using the formula: - Side length = Volume (V)^(1/3) - Side length = 8 cubic meters^(1/3) - Side length = 2 meters

- Area (A) = 2 meters * 2 meters - Area (A) = 4 square meters

- Pressure (P) = 62720 N / 4 square meters - Pressure (P) = 15680 Pascals

Therefore, the pressure exerted by the oil on the bottom of the tank is 15680 Pascals.