Question

Тело двигалось равномерно со скоростью 54 км/ч, а затем при торможении в течение 3,0 с остановилось. Определить путь, пройденный телом за все время движения, если оно продолжалось 6,8 с

Answer 1

T = 6.8 c
t2 = 3 c
t1 = t- t2 = 6.8 -3 = 3.8 c
V1 = 54 км/ч = 15 м/с  ; S1 =V1*t1 =15 * 3.8 =57 м
V2cp =(15+0) /2 = 7.5 м/с ; S2 = V2cp * t2 = 7.5 *3 =22,5 м
S = S1 +S2 = 57 + 22.5 =79,5 м
ОТВЕТ  79,5 м

Answer 2

Problem Analysis

We are given that an object initially moves with a constant speed of 54 km/h and then comes to a stop during a braking period of 3.0 seconds. We need to determine the total distance traveled by the object during the entire motion, which lasts for 6.8 seconds.

Solution

To solve this problem, we can break it down into two parts: the distance traveled during the constant speed motion and the distance traveled during the braking period.

# Distance Traveled during Constant Speed Motion

During the constant speed motion, the object covers a certain distance. We can calculate this distance using the formula:

Distance = Speed x Time

Given that the speed is 54 km/h and the time is 6.8 seconds, we need to convert the speed to meters per second to match the time unit. We know that 1 km/h is equal to 1000 meters per hour, and 1 hour is equal to 3600 seconds. Therefore, we can convert the speed as follows:

Speed = 54 km/h x (1000 m/km) / (3600 s/h) = 15 m/s

Now we can calculate the distance traveled during the constant speed motion:

Distance = Speed x Time = 15 m/s x 6.8 s = 102 m

Therefore, the distance traveled during the constant speed motion is 102 meters.

# Distance Traveled during Braking Period

During the braking period, the object comes to a stop. Since the object is no longer moving, the distance traveled during this period is zero.

# Total Distance Traveled

To find the total distance traveled by the object, we need to add the distance traveled during the constant speed motion to the distance traveled during the braking period:

Total Distance = Distance during Constant Speed Motion + Distance during Braking Period = 102 m + 0 m = 102 m

Therefore, the total distance traveled by the object during the entire motion is 102 meters.

Conclusion

The object traveled a total distance of 102 meters during its motion, with 102 meters covered during the constant speed motion and 0 meters covered during the braking period.