Question

Математический маятник имеет длину 90 см. Чему равен период колебаний этого маятника?

Answer 1

T=2*πКОРЕНЬ ИЗ M/G
T=2*πкорень из(90*10^-2/10)
t=2*π*0.3=1,884 примерно равно 2( если округлить )

Answer 2

Calculating the Period of a Mathematical Pendulum

A mathematical pendulum's period can be calculated using the formula:

Period (T) = 2π * √(Length of the pendulum (l) / Acceleration due to gravity (g))

Given that the length of the pendulum is 90 cm, we can calculate the period of oscillation using the above formula.

Calculation

Using the given length of the pendulum (l) as 90 cm, and the standard acceleration due to gravity (g) as approximately 9.81 m/s^2, we can calculate the period of oscillation.

Period (T) = 2π * √(90 cm / 9.81 m/s^2)

Converting the length of the pendulum to meters: 90 cm = 0.9 m

Now, substituting the values into the formula: Period (T) = 2π * √(0.9 / 9.81) Period (T) ≈ 2π * √(0.0917) Period (T) ≈ 2π * 0.3031 Period (T) ≈ 1.906 s

Therefore, the period of oscillation of the given mathematical pendulum with a length of 90 cm is approximately 1.906 seconds.

References

1. Source "1 2 . ."