Question

По шару массой 2 кг ударяют кием после чего он движется со скоростью 3 м/с и ударяется о второй шар массой 1 кг находящийся в покое . Определите скорость шаров после удара

Answer 1

Дано
m=2кг
v=10м/с
а=60°
М=20кг
найти p1

импульс шара р=mv
его проекция на ось х ( на горизонтальную ось) px=p*cosa
по закону сохранения импульса именно этот импульс и будет у платформы м шаром после столкновения. М тут лишнее.
px=mvcosa= 2кг*10 м/с *cos60°= 2кг*10 м/с *1/2=10 кг*м/c

Answer 2

2•3=6 м/с
вот и всё легкотня

Answer 3

Problem Analysis

We are given two balls, one with a mass of 2 kg and the other with a mass of 1 kg. The first ball strikes the second ball with a certain velocity, and we need to determine the velocities of both balls after the collision.

Solution

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) is defined as:

p = m * v

where p is the momentum, m is the mass, and v is the velocity.

Let's denote the velocity of the first ball before the collision as v1_initial, the velocity of the second ball before the collision as v2_initial, the velocity of the first ball after the collision as v1_final, and the velocity of the second ball after the collision as v2_final.

According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision:

m1 * v1_initial + m2 * v2_initial = m1 * v1_final + m2 * v2_final

Substituting the given values, we have:

2 kg * 3 m/s + 1 kg * 0 m/s = 2 kg * v1_final + 1 kg * v2_final

Simplifying the equation, we get:

6 kg m/s = 2 kg * v1_final + 1 kg * v2_final

Since the second ball is initially at rest (v2_initial = 0 m/s), we can simplify the equation further:

6 kg m/s = 2 kg * v1_final + 1 kg * 0 m/s

6 kg m/s = 2 kg * v1_final

Now, we can solve for v1_final:

v1_final = (6 kg m/s) / (2 kg) = 3 m/s

Therefore, the velocity of the first ball after the collision is 3 m/s.

To find the velocity of the second ball after the collision (v2_final), we can substitute the value of v1_final into the conservation of momentum equation:

2 kg * 3 m/s + 1 kg * 0 m/s = 2 kg * 3 m/s + 1 kg * v2_final

Simplifying the equation, we get:

6 kg m/s = 6 kg m/s + 1 kg * v2_final

Subtracting 6 kg m/s from both sides of the equation, we have:

0 kg m/s = 1 kg * v2_final

Therefore, the velocity of the second ball after the collision is 0 m/s.

Answer

After the collision, the first ball will have a velocity of 3 m/s and the second ball will have a velocity of 0 m/s.