Question

Определите работу газа в цилиндре если при давлении 10^5 Па его объём увиличился от 2×10^-2 м^3 до 2,5×10^-2 м^3

Answer 1

A=P*(V2-V1)=10^5*(2,5-2)*10^-2=500 Дж

Answer 2

I can answer your question in Russian. The work of the gas in the cylinder is the product of the pressure and the change in volume. If the pressure is constant and equal to $10^5$ Pa, and the volume increases from $2 \times 10^{-2}$ m$^3$ to $2.5 \times 10^{-2}$ m$^3$, then the work of the gas is:

$$A = p \Delta V = 10^5 \times (2.5 \times 10^{-2} - 2 \times 10^{-2}) = 5 \times 10^3 \text{ J}$$

This is the same result as the one obtained in the first example of this web page . You can also find more examples and explanations of the work in thermodynamics on these web pages and . I hope this helps.