Question

Тело свободно падает с высоты 10 м какова скорость тела на высоте 6м от поверхности земли ?(~9м/с)

Answer 1

Высота 6 метров означает, что тело пролетело s=10м-6м=4м
s=gt²/2
t- время, которое тело затратило на путь s. найдём t.
t²=2s/g
t=√(2s/g)
скорость через время t 
v=gt=g√(2s/g)= √(2gs)=√(2*10 м/с²*4м)=√(80 м²/с²)=4√5 м/с=8,94 м/с.Наверное вот так но я сомневаюсь.

Answer 2

To calculate the velocity of the body at a height of 6 meters from the surface of the Earth, we can use the principles of free fall and conservation of energy.

When the body is freely falling, it only has kinetic energy and potential energy. At the initial height of 10 meters, the body has potential energy, which gets converted into kinetic energy as it falls.

The potential energy (PE) at a height h is given by: PE = m * g * h

Where: m = mass of the body (assumed to be constant) g = acceleration due to gravity (approximately 9.81 m/s² on Earth) h = height from the surface of the Earth

The kinetic energy (KE) of the body is given by: KE = (1/2) * m * v^2

Where: v = velocity of the body at the given height

Since energy is conserved, the potential energy at the initial height (10 meters) is equal to the sum of kinetic energy and potential energy at the given height (6 meters): m * g * 10 = (1/2) * m * v^2 + m * g * 6

We can solve this equation to find the velocity (v) at the height of 6 meters: v^2 = 2 * g * (10 - 6) v^2 = 2 * 9.81 * 4 v^2 = 78.48

v ≈ √78.48 v ≈ 8.86 m/s

So, the velocity of the body at a height of 6 meters from the surface of the Earth is approximately 8.86 m/s. The value provided in the question (~9 m/s) seems to be a close approximation.