Question

V0=20 м/с V1=0 м/c g=10 t-?

Answer 1

V1=V0+gt

t=(V1-V0)/g

t=(0-20)/10=2 (c)

Answer 2

t=(V1-V0):g

t=(0-20):10=2 с

Answer 3

To solve for time (t), we can use the kinematic equation that relates initial velocity (V0), final velocity (V1), acceleration (g), and time (t):

V1 = V0 + gt

Where: V0 = Initial velocity = 20 m/s V1 = Final velocity = 0 m/s (since the object comes to a stop) g = Acceleration due to gravity = 10 m/s²

Now, let's rearrange the equation to solve for time (t):

t = (V1 - V0) / g

Substitute the given values:

t = (0 - 20) / 10 t = -20 / 10 t = -2 seconds

The negative sign indicates that the object will take 2 seconds to come to a stop after being launched vertically upwards. However, in most cases, time should be positive, and since we are dealing with the upward motion, it is better to consider the magnitude of the time, which is 2 seconds.