Question

V1=5,5м/с m1=60кг m2=240кг v2=?

Answer 1

V1=m1
v1x=m2
v2=v1*m2/m1=5,5*240/60=22

Answer 2

To find the velocity (v2) of the second object (m2 = 240 kg) after the collision, we can use the principle of conservation of momentum. In a collision between two objects, the total momentum before the collision is equal to the total momentum after the collision, provided no external forces are acting on the system during the collision.

The momentum (p) of an object is given by the product of its mass (m) and its velocity (v):

p = m * v

Before the collision, the total momentum of the system is:

Total momentum before = m1 * v1 + m2 * v2

After the collision, the total momentum remains the same:

Total momentum after = m1 * v1' + m2 * v2'

where v1' and v2' are the velocities of m1 and m2 after the collision, respectively.

Since we are given the values of m1, v1, and m2 and we want to find v2, we can rearrange the equation to solve for v2:

m1 * v1 + m2 * v2 = m1 * v1' + m2 * v2'

Since there are no external forces, we can assume that the only interaction is between m1 and m2. Thus, we can consider the collision as a one-dimensional collision and use the formula for the conservation of momentum in the x-direction:

m1 * v1_initial + m2 * v2_initial = m1 * v1_final + m2 * v2_final

where v1_initial and v2_initial are the initial velocities, and v1_final and v2_final are the final velocities of the two objects.

Plugging in the given values:

m1 * v1 + m2 * v2 = m1 * 0 + m2 * v2_final

Since m1 collides with an object of much larger mass (m2), we can assume that m1 comes to rest after the collision (v1_final = 0). Solving for v2_final:

m2 * v2 = m2 * v2_final

v2_final = v2

Now, we can calculate v2:

v2 = v2_final = v2_initial = (m1 * v1) / m2

Substitute the given values:

v2 = (60 kg * 5.5 m/s) / 240 kg v2 = 330 / 240 v2 ≈ 1.375 m/s

So, the velocity of the second object (m2) after the collision is approximately 1.375 m/s.