
L=5смI=10Ar1=4смr2=3смB=?


Ответы на вопрос

Ответ:
B=9 c=17 альфа = 80 как то так



To calculate the magnetic field (B) at a distance r2 from a long straight conductor carrying current I, we can use Ampere's law. Ampere's law states that the magnetic field (B) at a distance (r) from an infinitely long straight conductor carrying current (I) is given by:
B = (μ₀ * I) / (2π * r)
where: B is the magnetic field in tesla (T). μ₀ is the permeability of free space, approximately 4π x 10^(-7) T m/A. I is the current in amperes (A). r is the distance from the conductor in meters (m).
Given: L = 5 cm = 0.05 m (length of the conductor), I = 10 A (current in the conductor), r1 = 4 cm = 0.04 m (distance from the conductor), r2 = 3 cm = 0.03 m (distance for which we want to calculate the magnetic field).
First, let's calculate the magnetic field (B) at a distance r1:
B1 = (μ₀ * I) / (2π * r1) B1 = (4π x 10^(-7) T m/A * 10 A) / (2π * 0.04 m) B1 = (4π x 10^(-6) T) / (0.08π m) B1 = 5 x 10^(-6) T
Now, let's calculate the magnetic field (B) at a distance r2:
B2 = (μ₀ * I) / (2π * r2) B2 = (4π x 10^(-7) T m/A * 10 A) / (2π * 0.03 m) B2 = (4π x 10^(-6) T) / (0.06π m) B2 = 6.67 x 10^(-5) T
Therefore, the magnetic field (B) at a distance of 3 cm (r2) from the conductor is approximately 6.67 x 10^(-5) Tesla (T).


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