Question

F1=20H F2=420H L2=2см L1=?

Answer 1

Ответ:

0.42м

Объяснение:

F1/F2=l2/l1

l1=F2*l2/F1

l1=420*0,02/20=0,42м

Answer 2

It appears you're providing some information related to inductance (F) and the number of turns (N) for two coils, but the information is not entirely clear. In electrical engineering, inductance is typically denoted by the symbol "L" (not "F"), and the unit of inductance is the henry (H). It's also important to clarify the relationship between the parameters you've given.

Here's how you can interpret your data:

1. F1 = 20 H: This is the inductance of the first coil.

2. F2 = 420 H: This is the inductance of the second coil.

3. L2 = 2 cm: This seems to be the length of the second coil, but the length alone isn't enough to calculate inductance.

To calculate the inductance (L1) of the first coil (assuming it's a solenoid or a similar configuration), you need more information, such as the number of turns (N1) and possibly the coil dimensions.

The formula for the inductance of a solenoid coil is:

L = (μ₀ * N² * A) / l

Where:

• L is the inductance (in henrys, H).
• μ₀ (mu-naught) is the permeability of free space (approximately 4π x 10⁻⁷ H/m).
• N is the number of turns.
• A is the cross-sectional area of the coil.
• l is the length of the coil.

Without the number of turns (N1) and the cross-sectional area (A1) of the first coil, you cannot calculate the inductance (L1). Please provide this missing information for a more precise calculation.