Question

M1L +m,с (t2-t1)=m2c2(t-t3) M? C2? t?

Answer 1

Ответ:

Объяснение:

1)

M₁·λ + m·c(t₂ - t₁) = m₂·c₂·(t - t₃)

M₁ =  ( m₂·c₂·(t - t₃) - m·c(t₂ - t₁)) / λ

2)

c₂ = (M₁·λ + m·c(t₂ - t₁)) / (m₂·(t - t₃))

3)

m₂·c₂·(t - t₃) = M₁·λ + m·c(t₂ - t₁)

t - t₃ = (M₁·λ + m·c(t₂ - t₁)) / (m₂·c₂)

t = t₃ +(M₁·λ + m·c(t₂ - t₁)) / (m₂·c₂)

Answer 2

It looks like you've written an equation, but it's not entirely clear what you're asking. Let me break down the variables and symbols in your equation:

• M1 and M2: These are presumably the masses of two objects.
• c: This is the speed of light in a vacuum, approximately 299,792,458 meters per second.
• t1 and t2: These seem to be two different times.
• t3: This appears to be another time.
• m: It's not clear what this represents in the context of the equation.
• c^2: This represents the square of the speed of light.

The equation itself seems to be some form of energy-momentum equation or perhaps a relativistic equation, but it's not clear what specific physical situation it represents.

If you have a specific question or need clarification on any part of this equation or its context, please provide more details, and I'll do my best to assist you.