Question

Обкладки плоского воздушного конденсатора имеют заряды +10-7 Кл и -10-7 Кл. Разность потенциалов между обкладками составляет 20 В. Определить энергию конденсатора.

Answer 1

Ответ:

Объяснение:

Дано:

|q| = 1·10⁻⁷ Кл

U = 20 В

________

W - ?

W = q·U / 2 = 1·10⁻⁷·20 / 2 = 1·10⁻⁶  Дж   или   1 мкДж

Answer 2

Calculation of the Energy of a Capacitor

To determine the energy of a capacitor, we can use the formula:

E = (1/2) * C * V^2

Where: - E is the energy stored in the capacitor, - C is the capacitance of the capacitor, and - V is the potential difference (voltage) across the capacitor.

In this case, the potential difference between the plates of the capacitor is given as 20 V, and the charges on the plates are +10^-7 C and -10^-7 C.

To find the capacitance, we can use the formula:

C = Q / V

Where: - C is the capacitance