Question

15 балов При нагревании куска металла массой 200 г от 20 °С до 60 °С его внутренняя энергия увеличилась на 2400 Дж. Какова удельная теплоёмкость металла? Ответ запишите в Дж/(кг·°С). В ответе укажите только число, еденицы измерения указывать не нужно.

Answer 1

Ответ:

1200

Объяснение:

..........................

Answer 2

Calculation of Specific Heat Capacity

To calculate the specific heat capacity of the metal, we can use the formula:

Q = mcΔT

Where: - Q is the change in internal energy of the metal (in Joules), - m is the mass of the metal (in kilograms), - c is the specific heat capacity of the metal (in Joules per kilogram per degree Celsius), and - ΔT is the change in temperature of the metal (in degrees Celsius).

In this case, we are given the following information: - Mass of the metal (m) = 200 g = 0.2 kg - Change in temperature (ΔT) = 60 °C - 20 °C = 40 °C - Change in internal energy (Q) = 2400 J

Using the formula, we can rearrange it to solve for the specific heat capacity (c):

c = Q / (m * ΔT)

Substituting the given values:

c = 2400 J / (0.2 kg * 40 °C)

Calculating the value:

c = 2400 J / 8 kg °C

c ≈ 300 J/(kg·°C)

Therefore, the specific heat capacity of the metal is approximately 300 J/(kg·°C).