Question

сколько энергии выделилось при охлаждении куска меди массой 40г на 150*C удельная теплота меди равна 400дж(кг*С)

Answer 1

Ответ:

2400 Дж

Объяснение:

m=0.04 кг    Δt=150 °C     c=400 Дж/(кг*С)   Q=?

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Q=c*m*Δt=400*0.04*150=2400 Дж

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Answer 2

Calculation of Energy Released during Cooling of Copper

To calculate the amount of energy released during the cooling of a piece of copper, we can use the formula:

Q = m * c * ΔT

Where: - Q is the amount of energy released (in joules) - m is the mass of the copper (in kilograms) - c is the specific heat capacity of copper (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Given: - Mass of copper (m) = 40 grams = 0.04 kilograms - Specific heat capacity of copper (c) = 400 J/(kg*C) - Change in temperature (ΔT) = 150°C

Let's substitute these values into the formula and calculate the energy released:

Q = 0.04 kg * 400 J/(kg*C) * 150°C

Calculating this expression gives us:

Q = 2400 J

Therefore, the amount of energy released during the cooling of a 40-gram piece of copper from 150°C is 2400 joules.