Question

Частота обертання барабана пральної машини 1200об./хв.Чому дорівнює період обертання барабана? З якою швидкістю обертається при віджиманні білизна, якщо радіус барабана 30 см?

Answer 1

Ответ:

дано f=1200 об/мин=1200/60=20 об/с t=300 с T- ? N- ?

T=1/f=1/20=5/100=0,05 с - период

f=N/t

N=f*t=20 об/с*300с=6000 оборотов

Ответ N=6000 T=0,05 с

Answer 2

The Period of Rotation of the Drum

The period of rotation of the drum in a washing machine can be determined using the formula:

Period (T) = 1 / Frequency (f)

In this case, the frequency of rotation is given as 1200 rotations per minute (rpm), which can be converted to rotations per second (rps) by dividing by 60:

Frequency (f) = 1200 rpm / 60 = 20 rps

Using the formula, we can calculate the period of rotation:

Period (T) = 1 / 20 rps = 0.05 seconds

Therefore, the period of rotation of the drum is 0.05 seconds.

Speed of Rotation during Spin Cycle

To determine the speed of rotation during the spin cycle, we can use the formula for linear speed:

Linear Speed (v) = 2 * π * Radius (r) * Frequency (f)

In this case, the radius of the drum is given as 30 cm, which can be converted to meters by dividing by 100:

Radius (r) = 30 cm / 100 = 0.3 meters

Using the formula, we can calculate the linear speed:

Linear Speed (v) = 2 * π * 0.3 meters * 20 rps = 12 π meters per second

Therefore, the speed of rotation during the spin cycle is approximately 37.7 meters per second.

Please note that the actual speed may vary depending on the specific washing machine model and its settings.